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Ex 2.2, 8Find the value of tan-1 ["2 cos " (2"sin−1" 1/2)]Solving sin-1 (𝟏/𝟐)Let y = sin-1 (1/2) sin y = 1/2sin y = sin (𝝅/𝟔)Range of principal value of sin −1 is [(−𝜋)/2, ( 𝜋)/2]Hence, y = 𝝅/𝟔RoughWe know that sin 30° = 1/2θ = 30° = 30 × 𝜋/180 = 𝜋/6Si

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